(18x^2-3x+4)/(6x+5)

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Solution for (18x^2-3x+4)/(6x+5) equation: 


D( x )

6*x+5 = 0

6*x+5 = 0

6*x+5 = 0

6*x+5 = 0 // - 5

6*x = -5 // : 6

x = -5/6

x in (-oo:-5/6) U (-5/6:+oo)

(18*x^2-(3*x)+4)/(6*x+5) = 0

(18*x^2-3*x+4)/(6*x+5) = 0

18*x^2-3*x+4 = 0

18*x^2-3*x+4 = 0

DELTA = (-3)^2-(4*4*18)

DELTA = -279

DELTA < 0

1 = 0

1/(6*x+5) = 0

x belongs to the empty set

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